Lecture 6
A perfectly competitive firm’s problem: \[\max_q \; P \cdot q - C(q)\]
First-order condition: \[P = MC(q)\]
A monopolist’s problem: \[\max_Q \; P(Q) \cdot Q - C(Q)\] First-order condition: \[\underbrace{P(Q) + Q \cdot P'(Q)}_{MR(Q)} = MC(Q)\]
Why are price and marginal revenue different for a monopolist?
Monopolist maximizes: \[\max_Q \; \pi(Q) = P(Q) \cdot Q - C(Q)\]
First-order condition: \[\frac{d\pi}{dQ} = MR(Q) - MC(Q) = 0\]
Where marginal revenue is: \[MR(Q) = \underbrace{P(Q)}_{\text{output effect}} + \underbrace{Q \cdot P'(Q)}_{\text{price effect}}\]
Since \(P'(Q) < 0\), we always have \(MR(Q) < P(Q)\). The monopolist produces where \(MR(Q^*_m) = MC(Q^*_m)\), then charges \(P^*_m = P(Q^*_m) > MC\).
From \(MR = P + Q \cdot P'(Q)\), we can express marginal revenue in terms of the price elasticity of demand \(\varepsilon_D\):
\[MR = P\!\left(1 + \frac{1}{\varepsilon_D}\right) = P\!\left(1 - \frac{1}{|\varepsilon_D|}\right)\]
Setting \(MR = MC\):
\[\boxed{\frac{P - MC}{P} = \frac{1}{|\varepsilon_D|}}\]
The Lerner Index (markup over price) equals the inverse of the absolute elasticity. More inelastic demand → larger markup.
If demand curve takes constant elasticity form \(Q = a P^{-\varepsilon}\) and marginal cost is constant at \(c\), what price will the monopolist charge?
Technical Barriers
Legal Barriers
Strategic Behavior
Do we think this is generally welfare-improving?
Most markets are neither perfect competition nor monopoly.
Oligopoly: A market with a small number of firms whose decisions are interdependent i.e. each firm’s optimal choice depends on what the others do.
How do firms compete in oligopoly? How do they react to each other’s actions? Do they set prices or quantities?
Before we move on, we will define one concept from game theory that will be useful for analyzing oligopoly: Nash equilibrium.
Game theory studies strategic interactions between rational decision-makers and hence is a natural tool for analyzing oligopoly where firms’ decisions are interdependent.
A Nash equilibrium is a set of strategies (one for each player) such that no player can improve their payoff by unilaterally changing their strategy, given the strategies of the others.
Setup:
Key question: What prices will the firms choose?
Suppose firm 1 sets \(p_1 > c\).
Nash equilibrium: \(p_1^* = p_2^* = c\)
Both firms price at marginal cost reaching the competitive outcome (with just two firms!)
This is the Bertrand paradox: two firms are enough to eliminate all market power.
Why is \(p_1^* = p_2^* = c\) a Nash equilibrium?
Can either firm profit by deviating?
No profitable deviation exists. ✓
Why can’t \(p_1 = p_2 > c\) be an equilibrium?
Either firm could undercut by \(\epsilon\) and capture the entire market, roughly doubling its profit.
Real oligopolies earn positive profits. The Bertrand model misses something. Key extensions:
Setup:
Key difference from Bertrand: Firms commit to production levels, and the market clears at whatever price equates demand and supply.
Firm 1 maximizes: \[\pi_1 = P \cdot q_1 - c \cdot q_1 = [a - b(q_1 + q_2)]q_1 - cq_1\]
FOC: \[\frac{\partial \pi_1}{\partial q_1} = a - 2bq_1 - bq_2 - c = 0\]
Best response function: \[q_1^*(q_2) = \frac{a - c}{2b} - \frac{q_2}{2}\]
By symmetry: \(q_2^*(q_1) = \frac{a - c}{2b} - \frac{q_1}{2}\)
In a symmetric equilibrium, \(q_1 = q_2 = q^*\):
\[q^* = \frac{a - c}{2b} - \frac{q^*}{2} \implies q^* = \frac{a - c}{3b}\]
Total output: \(Q^* = 2q^* = \frac{2(a-c)}{3b}\)
Price: \(P^* = a - bQ^* = \frac{a + 2c}{3}\)
Profit per firm: \(\pi^* = (P^* - c) q^* = \frac{(a-c)^2}{9b}\)
Note: \(P^* > c\), so firms earn positive profits unlike Bertrand!
| Price | Total Output | Profit | |
|---|---|---|---|
| Competition | \(c\) | \((a-c)/b\) | \(0\) |
| Cournot | \((a+2c)/3\) | \(2(a-c)/(3b)\) | \((a-c)^2/(9b)\) |
| Monopoly | \((a+c)/2\) | \((a-c)/(2b)\) | \((a-c)^2/(4b)\) |
Cournot lies between competition and monopoly.
Demand: \(P = 100 - Q\), where \(Q = q_1 + q_2\). Both firms have \(MC = 20\).
Firm 1’s best response: \[q_1^* = \frac{100 - 20 - q_2}{2} = 40 - \frac{q_2}{2}\]
Symmetric equilibrium: \(q^* = 40 - q^*/2 \implies q^* = 80/3 \approx 26.67\)
Total output: \(Q^* \approx 53.33\)
Price: \(P^* \approx \$46.67\)
Profit per firm: \(\pi^* = (46.67 - 20)(26.67) \approx \$711\)
Compare: Monopoly profit = \(\$1{,}600\), so total Cournot profit (\(\$1{,}422\)) is less.
At the collusion point, each firm produces \(q_m/2 = 20\) and earns \(\$800\).
But from firm 1’s perspective: If firm 2 is producing \(20\), firm 1’s best response is:
\[q_1^* = 40 - \frac{20}{2} = 30\]
Firm 1 can earn more by producing 30 instead of 20. Each firm has an incentive to cheat on the collusive agreement. This is essentially a Prisoner’s Dilemma (we will talk about this more when we cover game theory).
With \(n\) identical firms, the symmetric equilibrium:
\[q^* = \frac{a - c}{(n+1)b}, \qquad Q^* = \frac{n(a - c)}{(n+1)b}, \qquad P^* = \frac{a + nc}{n+1}\]
Lerner index: \[L = \frac{P^* - c}{P^*} = \frac{a - c}{a + nc}\]
As \(n \to \infty\): \(P^* \to c\) converges to perfect competition
As \(n = 1\): reduces to monopoly
Market power decreases rapidly with the number of firms. Even 4–5 firms gets most of the way to the competitive outcome.